Problem
What is the self-potential energy of a thin spherical shell of radius \(R\), mass \(M\), and charge \(Q\), assuming uniform surface distributions of mass and charge?
Solution
The total self-potential energy is the sum of gravitational and electrostatic self-energies.
1. Gravitational self-energy
Using the standard result for a thin spherical shell,
\[
U_g=-\frac{GM^2}{2R}
\]
2. Electrostatic self-energy
Using the capacitance of an isolated spherical shell,
\[
C=4\pi\epsilon_0R
\]
The electrostatic self-energy is
\[
\begin{aligned}
U_e&=\frac{Q^2}{2C}\\[6pt]
&=\frac{Q^2}{8\pi\epsilon_0R}
\end{aligned}
\]
3. Total self-potential energy
Adding the gravitational and electrostatic contributions,
\[
U=U_g+U_e
\]
Final Answer
\[
\boxed{
U=\frac{1}{2R}
\left(
\frac{Q^2}{4\pi\epsilon_0}-GM^2
\right)
}
\]
In the animation below, the gravitational potential energy illustration is shown first in which particles assemble to form spherical shell coming from infinity. Subsequently, the electrostatic potential energy illustration is shown in which charges assemble on the spherical shell coming from infinity.