INDIAN INSTITUTES OF TECHNOLOGY and IT-BHU | |
JOINT ENTRANCE EXAMINATION 2005 | |
Screening Test on | One Question Paper (Objective type) of 3 hour duration in Mathematics, Chemistry and Physics |
Main Examination* on | Three Question Papers of 2 hour duration each in Mathematics, Chemistry and Physics |
(*Only for those who qualify in the Screening Test of JEE-2005) Syllabus for the Screening Test as well as for the Main Examination will be same. The detailed syllabus will be available in the Information Brochure of JEE-2005. Application Forms and Information Brochures will be Available from Details will be published in leading National Dailies and Employment News / Rozgar Samachar on Organising Chairman | |
If the sum of the coefficients in the expansion of $(x+y)^n$ is 4096, then the greatest coefficient in the expansion is _ _ _ _ . Solution $C_0 + C_1 + C_2 + C_3 + ......................... + C_n =4096 $ $\therefore 2^n = 4096 =2^{12} $ $\Rightarrow n = 12 $ Greatest coefficient = ${}^{12}{C_6} = 924$