It does appear at this moment that JEE is likely to be easier. IIT is known as a brand in India and abroad and is a mark of prestige for this country. An institute is known by its people, the greatest percentage of those are the students. If IIT has brand equity, the large share of it is due to the students. The students are selected via JEE and hence the examination pattern of JEE determines to a large extent the type of students that get into IIT. Anybody having view on this may send his/her article to articles@123iitjee.com or via poll comments displayed. This issue needs to be looked at from global perspective.
A man starts walking from the point P (-3, 4), touches the x-axis at R, and then turns to reach at the point Q (0, 2). The man is walking at a constant speed. If the man reaches the point Q in the minimum time, then $50 [(PR)^2 + (RQ)^2 ]$ is equal to _ _ _ _ . Solution For time to be minimum at constant speed, the directions must be symmetric. In other words, the angles made by PR and RQ with the vertical must be the same just like in the law of reflection in optics. $tan \theta = \frac {MP}{MR} = \frac {NQ}{NR} $ $\Rightarrow \frac {3-r}{4} = \frac {r}{2}$ $\Rightarrow r=1 $ So, $R \equiv ( - 1,0)$ Now, $50(PR^2+RQ^2)=50[(4+16)+(1+4)]=1250$