Q a projectile from a point O on the ground must hit a target P such that OP = 120 m The height of P from the ground is 60 m The minimum suitable velocity of projection is
(A ) 28 m/s (B ) 54 m/s (C ) 34 m/s ( D ) 42 m/s
IN THE SOLUTION PART THE FOLLOWING FORMULA IS USED
V min = √ g ( y + √ x ^2 + y ^2 ) AND THEY FOUND ANS ( D ) .
I DID NOT UNDERSTAND THIS FORMULA AND FROM WHERE THEY HAVE TAKEN .
Kindly help me in this regards.
Swapnil s khandekar
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The solution is attached in terms of two scanned images. Click on the images to enhance clarity.
![](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_u0PUr3KsKWC5c93QGx9gk_1JkC3GD4H4ySZZyR3O29Mlec7hDTHUskZ6qX_ITVwKRzhQdzDGOxh1wKb93sA4GRJo082zt9opWr1O7xg1O9f8nS87S5lBByPjhBlSc8dPLdMUq5cZNpHxu-5ZCHJh3rR5peOZmnRFOi=s0-d)
![](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sfZvCLqRNVGJTXEPEXGlzc7WemmqeQrDo_P7WMqzn-DgL2puh2V6hTPqIGIpLZt3nD2AqqYF1dMrdN7_Bpd7uaARmrBJjDxrmqMEZhmP6DvEdAepn_m4nrQsaw18KG7zGCtakieXLrquwfTCHYqXDclLqmqavtFTc=s0-d)
(A ) 28 m/s (B ) 54 m/s (C ) 34 m/s ( D ) 42 m/s
IN THE SOLUTION PART THE FOLLOWING FORMULA IS USED
V min = √ g ( y + √ x ^2 + y ^2 ) AND THEY FOUND ANS ( D ) .
I DID NOT UNDERSTAND THIS FORMULA AND FROM WHERE THEY HAVE TAKEN .
Kindly help me in this regards.
Swapnil s khandekar
-------------------------------------------------------------------------------------------
The solution is attached in terms of two scanned images. Click on the images to enhance clarity.