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JEE 2013 Status

After the IIT Council meeting of 27th Jun. and subsequent Senate meetings of IITM, IITB and IITK the picture of JEE 2013 has become clearer. There is general agreement now in regards to the compromise formula (refer for 2013 in a sense that while there may be suggestions for improvisations, there is no bone of contention. Since, it is IITK that was the first to declare about its own separate entrance exam due to some issues in new entrance procedure, the latest IITK Senate resolution of July 28th can be considered to be vital in reducing the uncertainties for 2013. The draft IITK Senate resolution of July 28th for JEE 2013 is as follows:

On the matter of changes to the IIT JEE examination The IIT Kanpur Senate resolves as under:

1. The Joint Admission Board's (JAB) recommendations arrived at in its meeting on 23rd June 2012 and adopted by IIT Council (in its meeting on 27th June 2012) be accepted as an interim measure for JEE 2013 keeping in view the urgent need to remove uncertainties from the minds of students. However, the Senate recommends that:
a) in the interest of fairness the earlier eligibility condition (as of JEE 2012) be retained for students who have passed their Board Examination in 2012.
b) the decision on the number of students to be short-listed for IIT JEE 2013 should be based on the available data and the structure and nature of IIT JEE 2013.
c) a formal document containing all details of responsibilities and liabilities, time-lines, financial and all other logistic matters be signed with the organisation conducting the screening test that will be used to select students for the IIT JEE examination. 
2. For JEE 2014 and beyond a Senate committee be constituted that will study all aspects of the admission process and arrive at recommendations based on
a) sound methodological principles supported by data collected from appropriate original sources and
b) be broadly guided by the three main observations of the Senate made earlier, namely: i) the selection process be a two stage examination with stage-1 acting as a filter for stage-2, ii) both the design and conduct of the stage-2 examination should be completely owned by the IIT system iii) in addition to Physics, Chemistry, Mathematics students should also be tested for general aptitude and other skills at some stage.
3. The Senate also recommends that JAB should constitute a separate committee consisting of representatives nominated by Senates of the IITs to advise JAB on the nature of the IIT entrance test and the process of admission.

This officially means that IITK will not conduct any separate exam for 2013. While the suggestions of IITK can be seen from above, IITB has suggested that instead of short-listing 1,50,000 candidates for JEE-Advance, only about 50,000 candidates should be shortlisted. When next JAB meeting takes place, we can expect greater clarity in overall procedure. But, by and large now it is clear that for 2013 there would be one JEE for all IITs and other participating institutes like NITs etc. and there would be no AIEEE; PCM will be the key subjects and 12th board is going to be very vital.

If you are JEE 2013 applicant, you may do the following for your preparation till the formal announcement about the admission procedure is made: 
  • Pay maximum emphasis on P, C, M.
  • Follow the syllabus as per the core curriculum in Sciences and Maths by Council of all Boards of Secondary Education (COBSE) in 2010 which should be available with CBSE. Also, take into account the syllabus of IIT JEE 2012.
  • Pay great emphasis on 12th board, especially in i) Physics, ii) Chemistry, iii) Mathematics, iv) one language subject, v) best subject among the electives. Be accustomed to writing descriptive answers/solutions for 12th board & possibly JEE-Advance and prepare according to objective type of situations for JEE-Main.
Once formal announcement is made, you can make some amendments in the above points.

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$f(x)=x^6+2x^4+x^3+2x+3 $

$\mathop {\lim }\limits_{x \to 1} \frac{{{x^n}f(1) - f(x)}}{{x - 1}} = 44$


Let $f(x)=x^6+2x^4+x^3+2x+3,x \in R $. Then the natural number n for which $\mathop {\lim }\limits_{x \to 1} \frac{{{x^n}f(1) - f(x)}}{{x - 1}} = 44$ is _ _ _ _ . Solution Since the limit has $\left[ {\frac{0}{0}} \right]$ form, L.H. Rule is applicable. Thus, $\mathop {\lim }\limits_{x \to 1} n{x^{n - 1}}f(1) - f'(x) = 44$ $\therefore nf(1) - f'(1) = 44$ $\therefore n.9 - ({6.1^5} + {8.1^3} + {3.1^2} + 2.1) = 44$ $ \Rightarrow 9n - 19 = 44$ $\Rightarrow n=7$