JEE & Sound Engineering Education by IIT Alumnus

JEE & Sound Engineering Education by IIT Alumnus

The required area = shaded area in the figure = $\frac{1}{2}({5^2} - {3^2})\left( {\frac{\pi }{4} - \frac{\pi }{8}} \right)$

$ = \frac{1}{2} \times 16 \times \frac{\pi }{8} = \pi $ square unit.