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Physics Guru is an online education and competitive examinations preparation portal founded by Manish Verma, an IIT Madras alumnus, providing learning resources for competitive examinations.

The emphasis is on conceptual understanding, analytical thinking and problem solving rather than simply memorising formulas and standard methods.

The objective is to help students understand what they are learning and develop the ability to solve problems they have not seen before.

For a triangle, show that the point where altitude cuts circumcircle is the image of the orthocentre about the side.


Let ABC be triangle having H as orthocentre. The proof is given below for reflection about side BC. Similar approach can be used for reflections about other sides. 

To prove that HL = PL

Join BP. The idea is to prove that the triangles BLH and BLP are congruent.

Both triangles are right triangles having same base BL.

Arc PC subtends equal angles PBC and PAC.

$\angle PBC = \angle PAC$

From $\Delta ACL$, $\angle LAC = 90^\circ - C$

So, $\angle PBC = \angle PAC =\angle LAC = 90^\circ - C$

From, $\Delta BMC$, $\angle MBC = 90^\circ - C$

So, $\angle PBC = 90^\circ - C = \angle MBC$

From ASA congruence, triangles BLH and BLP are congruent.

From CPCT, HL = PL.