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The half-life of a radioactive nuclide is 100 hours ....

The half-life of a radioactive nuclide is 100 hours. The fraction of original activity that will remain after 150 hours would be:

(1) $\frac {1}{2}$                    (2) $\frac {1}{2\sqrt 2}$
(3) $\frac {2}{3}$                    (4) $\frac {2}{3\sqrt 2}$

Solution

Activity $A \propto N = \frac {N_0}{2^n}$

$A_0 \propto N_0 $

Fraction of original activity $\frac {A}{A_0}=\frac {1}{2^n}$, where n = number of half-lives

If half-life is 100 hours, number of half-lives in 150 hours = 1.5 = n

So, $\frac {A}{A_0}=\frac {1}{2^{1.5}}=\frac {1}{2\sqrt 2}$

Answer: (2)

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