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Physics Guru is an online education and competitive examinations preparation portal founded by Manish Verma, an IIT Madras alumnus, providing learning resources for competitive examinations.

The emphasis is on conceptual understanding, analytical thinking and problem solving rather than simply memorising formulas and standard methods.

The objective is to help students understand what they are learning and develop the ability to solve problems they have not seen before.

The maximum and minimum distances of a comet ....

The maximum and minimum distances of a comet from the Sun are $1.6 \times 10^{12}$ m and $8.0 \times 10^{10} $ m respectively. If the speed of the comet at the nearest point is $6 \times 10^4 $ m/s, the speed at the farthest point is:

(A) $3.0 \times 10^3 $ m/s
(B) $1.5 \times 10^3 $ m/s
(C) $4.5 \times 10^3 $ m/s
(D) $6.0 \times 10^3 $ m/s

Solution

We have, $v_1 r_1 = v_2 r_2 $

$\therefore v_1 \times 1.6 \times 10^{12} = 6 \times 10^4 \times 8.0 \times 10^ {10} $

$\Rightarrow v_1 = 3.0 \times 10^3 $ m/s

Answer: (A)