An empty LPG cylinder weighs 14.8 kg. When full, it weighs 29.0 kg and shows a pressure of 3.47 atm. In the course of use at ambient temperature, the mass of the cylinder is reduced to 23.0 kg. The final pressure inside the cylinder is _ _ _ _ atm. (Nearest integer)
(Assume LPG to be an ideal gas)
Solution
Weight of gas before use = 29.0 - 14.8 = 14.2 kg
Weight of gas after use = 23.0 - 14.8 = 8.2 kg
Now, $\frac {P_1}{n_1} = \frac {P_2}{n_2} $
$\therefore \frac {3.47}{14.2} = \frac {P_2}{8.2} $
$\Rightarrow P_2 = \frac {3.47 \times 8.2}{14.2} \approx 2 atm $
Answer: 2